CAT stands for common aptitude test. This topic is an integral part of many competitive exams. An aspirants could except few questions from this Team Formation topic. As Logical reasoning section contain a total of 20 questions and out of that few questions are from Team Formation. A Logical Reasoning & Data Interpretation contains 30% weightage in CAT exams.

Team Formation- Basic Concepts

Questions in Team Formation and Selection for CAT provide a set of people or a collection of objects. Additionally, they provide you with certain conditions. According to the conditions that are given, you must make choices to form the team. We recommend you to note down main points of the conditions from the data that is provided. Subsequently, each question may also introduce additional conditions to apply in certain scenarios. That’s why be mindful when reading the clauses and their relative situations.

In reasoning based on Team Formation, we arrange the given set of objects or people in different groups or select objects/people to form a group or a team in accordance with the given constraints and conditions.

Here a few tips that can help solve these questions are mention below. So have a look below:

1. As you go through the clues, make their visual representation so that you don’t have to read again.
2. Keep track of the people/objects that should not be included or included together while forming a group or a team.

Also read: CAT Preparation in 5 months : Toppers Strategy

Video’s that could help aspirant.

CAT Logical Reasoning questions | CAT Exam LR : Team Formation

Some important questions on team selection and logical grouping from previous year papers is show in the below which can help in the preparation of CAT and similar exams.

Question 1. A supermarket has to place 12 items (coded A to L) in shelves numbered 1 to 16. Five of these items are types of biscuits, three are types of candies and the rest are types of savouries. Only one item can be kept in a shelf. Items are to be placed such that all items of the same type are clustered together with no empty shelf between items of the same type and at least one empty shelf between two different types of items. At most two empty shelves can have consecutive numbers. (CAT 2019-Slot 1)

The following additional facts are known.

1. A and B are to be place in consecutively number of shelves in increasing order
2. I and J are to be place in consecutively number of shelves both higher number than the shelves in which A and B .
3. D, E and F are savouries and are to be place in consecutively number shelves in increasing order after all the biscuits and candies.
4. K is to be place in shelf number 16.
5. L and J are items of the same type, while H is an item of a different type.
6. C is candy and is to be place in a shelf preceded by two empty shelves.
7. L is to be place in a shelf preceded by exactly one empty shelf.

Answer the questions that follow:

Question1 : In how many different ways can the items be arrange on the shelves?

1. 4
2. 2
3. 8
4. 1

Question2 : Which of the following items is not a type of biscuit?

1. A
2. L
3. B
4. G

Question3 : Which of the following can represent the numbers of the empty shelves in a possible arrangement?

1. 1,7,11,12
2. 1,5,6,12
3. 1,2,6,12
4. 1,2,8,12

Question4 : Which of the following statements is necessarily true?

1. There are two empty shelves between the biscuits and the candies
2. All candies is before biscuits
3. All biscuits is before candies.
4. There are at least four shelves between items B and C.

Solution:

Total number of Biscuits = 5. Total number of Candies = 3. So The Total number of Savouries = 12 – 5 – 3 = 4

From point iii) and iv) it is clear that D, E, F and K are 4 savouries and are kept in shelves numbered 13,14, 15 and 16 as there is no empty shelf between items of the same type. From point II), V and VII) I, J and L are of the same type. L being in the least numbered shelf among 3. As from point VI,) C is candy so I, J and L must be Biscuits as there are only 3 candies.

From point V) H is not Biscuits so it must be a candy thus A and B must be Biscuits. Now Item can be placed as given below.

Case 1) when all biscuits is place after candies.

Case 2) When all candies is place after biscuits.

Total 8 cases are possible.